Fourier Series Classroom
103.1 Even & Odd Functions
Understanding even and odd functions is crucial in Fourier series analysis because it can significantly simplify the calculation of coefficients. Functions can exhibit symmetry around the y-axis (even) or symmetry about the origin (odd).
- An **even function** $f(x)$ satisfies $f(-x) = f(x)$ for all $x$ in its domain. Its graph is symmetric with respect to the y-axis. Examples include $x^2$, $\cos(x)$, and $|x|$.
- An **odd function** $f(x)$ satisfies $f(-x) = -f(x)$ for all $x$ in its domain. Its graph is symmetric with respect to the origin. Examples include $x^3$, $\sin(x)$, and $1/x$.
Most functions are neither even nor odd, but any function can be decomposed into an even and an odd part.
💡 Explore Function Properties!
Dive deeper into function types and their properties in our Pre-Calculus Classroom!
Go to Pre-CalculusCheckpoint: Test your understanding!
103.2 Fourier Cosine & Sine Series
The symmetry of even and odd functions simplifies Fourier series calculations over symmetric intervals like $[-\pi, \pi]$ (or $[-L, L]$):
- If $f(x)$ is an **even function**, then $f(x)\sin(nx)$ is an odd function. The integral $\int_{-\pi}^{\pi} f(x)\sin(nx) \,dx = 0$, which means all $b_n = 0$. The Fourier series becomes a **Fourier Cosine Series**: $$f(x) = \frac{a_0}{2} + \sum_{n=1}^{\infty} a_n \cos(nx)$$ where $a_0 = \frac{2}{\pi} \int_{0}^{\pi} f(x) \,dx$ and $a_n = \frac{2}{\pi} \int_{0}^{\pi} f(x) \cos(nx) \,dx$.
- If $f(x)$ is an **odd function**, then $f(x)\cos(nx)$ is an odd function, and $\int_{-\pi}^{\pi} f(x)\cos(nx) \,dx = 0$, so all $a_n = 0$ (including $a_0$). The Fourier series becomes a **Fourier Sine Series**: $$f(x) = \sum_{n=1}^{\infty} b_n \sin(nx)$$ where $b_n = \frac{2}{\pi} \int_{0}^{\pi} f(x) \sin(nx) \,dx$.
This property allows us to integrate only over $[0, \pi]$ and multiply by $2/\pi$, simplifying computations.
🔢 Practice Integration!
Fourier coefficients require strong integration skills. Practice in our Calculus Applications Classroom!
Go to Calculus ApplicationsCheckpoint: Test your understanding!
103.3 Half-Range Fourier Series
When a function $f(x)$ is defined only on a finite interval $[0, \pi]$ (or more generally $[0, L]$), and we want to represent it using a Fourier series, we can extend it to the symmetric interval $[-\pi, \pi]$ (or $[-L, L]$) in two ways:
- **Even periodic extension:** Define $f(-x) = f(x)$ for $x \in (0, \pi]$. This creates an even function over $[-\pi, \pi]$ with period $2\pi$. The Fourier series will be a **Fourier Cosine Series**.
- **Odd periodic extension:** Define $f(-x) = -f(x)$ for $x \in (0, \pi]$. This creates an odd function over $[-\pi, \pi]$ with period $2\pi$. The Fourier series will be a **Fourier Sine Series**.
These are called "half-range" series because the original function is defined over half of the full period interval. The choice depends on the application or the desired behavior at the boundaries.
🧠 Ready for more practice?
Generate custom Fourier series problems with our Worksheet Generator!
Go to Worksheet GeneratorCheckpoint: Test your understanding!
104.1 Periodic Function (Period L)
The Fourier series definition can be generalized for any periodic function $f(x)$ with an arbitrary period $T = 2L$ (meaning the function is defined on an interval of length $2L$, e.g., $[-L, L]$ or $[c, c+2L]$). The generalized Fourier series is:
$$f(x) = \frac{a_0}{2} + \sum_{n=1}^{\infty} \left(a_n \cos\left(\frac{n\pi x}{L}\right) + b_n \sin\left(\frac{n\pi x}{L}\right)\right)$$The coefficients are given by:
$$a_0 = \frac{1}{L} \int_{-L}^{L} f(x) \,dx$$ $$a_n = \frac{1}{L} \int_{-L}^{L} f(x) \cos\left(\frac{n\pi x}{L}\right) \,dx \quad \text{for } n=1, 2, 3, \dots$$ $$b_n = \frac{1}{L} \int_{-L}^{L} f(x) \sin\left(\frac{n\pi x}{L}\right) \,dx \quad \text{for } n=1, 2, 3, \dots$$Here, $L$ is half of the period. If the period is given as $T$, then $L = T/2$. This allows us to analyze periodic functions of any period, not just $2\pi$.
📚 Review Periodic Functions!
Revisit the basics of periodic functions in our Fourier Series (Period $2\pi$) Introduction!
Go to Fourier Series IntroductionCheckpoint: Test your understanding!
Relevant Tools
To further enhance your learning and problem-solving skills, explore these additional resources
Loading relevant links...
104.2 Half-Range Series (Range L)
Similar to the $2\pi$ case, we can define half-range Fourier series for functions defined on an arbitrary interval $[0, L]$.
- **Fourier Cosine Series (for even extension):** $$f(x) = \frac{a_0}{2} + \sum_{n=1}^{\infty} a_n \cos\left(\frac{n\pi x}{L}\right)$$ $$a_0 = \frac{2}{L} \int_{0}^{L} f(x) \,dx$$ $$a_n = \frac{2}{L} \int_{0}^{L} f(x) \cos\left(\frac{n\pi x}{L}\right) \,dx$$
- **Fourier Sine Series (for odd extension):** $$f(x) = \sum_{n=1}^{\infty} b_n \sin\left(\frac{n\pi x}{L}\right)$$ $$b_n = \frac{2}{L} \int_{0}^{L} f(x) \sin\left(\frac{n\pi x}{L}\right) \,dx$$
In both cases, the extended function has a period of $2L$. These series are particularly useful for solving boundary value problems in partial differential equations where the solution is sought over a finite interval.
🧠 Test Your Knowledge!
Challenge yourself with quizzes on Fourier series in our Math Quizzes section!
Go to Math QuizzesCheckpoint: Test your understanding!